问题:求极限sin^2x/sin2x^2
求极限
结论/结果
1/2
解答
\lim_{x \rightarrow 0} \frac{\sin ^{2} x}{\sin 2 x^{2}}=\lim_{x \rightarrow 0} \frac{\sin ^{2} x}{x^2} ·\frac{2x^2}{\sin 2 x^{2}}·\frac{1}{2}=\frac{1}{2}
求极限
\lim_{x \rightarrow 0} \frac{\sin ^{2} x}{\sin 2 x^{2}}=\lim_{x \rightarrow 0} \frac{\sin ^{2} x}{x^2} ·\frac{2x^2}{\sin 2 x^{2}}·\frac{1}{2}=\frac{1}{2}