问题：判断对错lim√(x+3)-3/x-6
判断对错
结论/结果
正确
解答
\lim_{x \rightarrow 6} \frac{\sqrt{x+3}-3}{x-6}=\lim_{x \rightarrow 6} \frac{1}{\sqrt{x+3}+3}=\frac{1}{6}
判断对错
\lim_{x \rightarrow 6} \frac{\sqrt{x+3}-3}{x-6}=\lim_{x \rightarrow 6} \frac{1}{\sqrt{x+3}+3}=\frac{1}{6}