问题：求极限lim √(x+)-1/x
极限的运算
结论/结果
1/2
解答
\lim_{x \rightarrow 0} \frac{\sqrt{x+1}-1}{x}=\lim_{x \rightarrow 0} \frac{1}{\sqrt{x+1}+1}=\lim_{x \rightarrow 0} \frac{1}{\sqrt{0+1}+1}=\frac{1}{2}
极限的运算
\lim_{x \rightarrow 0} \frac{\sqrt{x+1}-1}{x}=\lim_{x \rightarrow 0} \frac{1}{\sqrt{x+1}+1}=\lim_{x \rightarrow 0} \frac{1}{\sqrt{0+1}+1}=\frac{1}{2}